我有一个场景，我想在只读事务中执行儿童1，在读写事务中执行儿童2，两者都在一个过拱形事务中。如果儿童1或儿童2出现问题，我只想回滚过拱形事务。

@Transactional
parentMethod(){
  TransactionSynchronizationManager
  .setCurrentTransactionName("TestTransaction");
  log.info("Current Transaction Name - parentMethod ::: " + 
  TransactionSynchronizationManager
  .getCurrentTransactionName());
  log.info("Is the transaction readonly - parentMethod ::: " + 
  TransactionSynchronizationManager.isCurrentTransactionReadOnly());
  child1();
  child2();
}

@Transactional(readOnly=true)
child1(){
  log.info("Current Transaction Name - child1 ::: " + 
  TransactionSynchronizationManager
  .getCurrentTransactionName());
  log.info("Is the transaction readonly - child1 ::: " + 
  TransactionSynchronizationManager
  .isCurrentTransactionReadOnly());
}

@Transactional
child2(){
  log.info("Current Transaction Name - child2 ::: " + 
  TransactionSynchronizationManager
  .getCurrentTransactionName());
  log.info("Is the transaction readonly - child2 ::: " + 
  TransactionSynchronizationManager
  .isCurrentTransactionReadOnly());
}

输出日志显示：

Current Transaction Name - parentMethod ::: TestTransaction
Is the transaction readonly - parentMethod ::: false
Current Transaction Name - child1 ::: null
Is the transaction readonly - child1 ::: false
Current Transaction Name - child2 ::: null
Is the transaction readonly - child2 ::: false

然而，如果我在child 1方法中故意设置TransactionSyn行吗izationManager. setCurrentTransactionReadOnly（true），则输出会像我预期的那样略有变化。

@Transactional(readOnly=true)
child1(){
  TransactionSynchronizationManager
  .setCurrentTransactionReadOnly(true);
  log.info("Current Transaction Name - child1 ::: " + 
  TransactionSynchronizationManager
  .getCurrentTransactionName());
  log.info("Is the transaction readonly - child1 ::: " + 
  TransactionSynchronizationManager
  .isCurrentTransactionReadOnly());
}

输出日志显示：

Current Transaction Name - parentMethod ::: TestTransaction
Is the transaction readonly - parentMethod ::: false
Current Transaction Name - child1 ::: null
Is the transaction readonly - child1 ::: true
Current Transaction Name - child2 ::: null
Is the transaction readonly - child2 ::: false

我只是想知道我正在做的事情是否有问题。或者有没有更好的方法来做到这一点。但是，目前的事务名称在儿童1和儿童2中仍然为空，我希望它是“TestTransaction”，这是在父母方法中设置的。

此外，只是想知道哪一个优先，只读还是传播级别，当有嵌套事务时，这些值设置不同。