我用where
和多个或where
与like
连接语句,下面是我尝试的,不幸的是,即使使用无效的like
值,它也不像这样工作,例如like%0000%
,我确信给定的like查询上没有这样的相关数据,但是下面的sql仍然返回行。 如有任何帮助,点子,不胜感激。
SELECT `a`.`id`, `a`.`subcategory_id`, `a`.`ps_id`, `b`.`id` AS `b_id`, `b`.`ps_keyword`, `b`.`created_at`
FROM `buss_subcategory_products_services` `a`
LEFT JOIN `buss_products_services` `b` ON `b`.`id` = `a`.`ps_id`
WHERE `b`.`is_deleted` =0
AND `a`.`subcategory_id` = '11'
OR (
`a`.`subcategory_id` = '1'
OR `a`.`subcategory_id` = '8'
OR `a`.`subcategory_id` = '5'
OR `a`.`subcategory_id` = '2'
OR `a`.`subcategory_id` = '3'
OR `a`.`subcategory_id` = '9'
OR `a`.`subcategory_id` = '4'
OR `a`.`subcategory_id` = '10'
OR `a`.`subcategory_id` = '6'
OR `a`.`subcategory_id` = '7'
)
AND `b`.`ps_keyword` LIKE '%xxxxxxxxxxxxxxxxxxxxxxxxxxxx%' ESCAPE '!'
ORDER BY `b`.`ps_keyword` ASC
这看起来是个合乎逻辑的问题。
这个:
WHERE
`b`.`is_deleted` =0
AND `a`.`subcategory_id` = '11'
OR (
`a`.`subcategory_id` = '1'
OR `a`.`subcategory_id` = '8'
OR `a`.`subcategory_id` = '5'
OR `a`.`subcategory_id` = '2'
OR `a`.`subcategory_id` = '3'
OR `a`.`subcategory_id` = '9'
OR `a`.`subcategory_id` = '4'
OR `a`.`subcategory_id` = '10'
OR `a`.`subcategory_id` = '6'
OR `a`.`subcategory_id` = '7'
)
AND `b`.`ps_keyword` LIKE '%xxxxxxxxxxxxxxxxxxxxxxxxxxxx%' ESCAPE '!'
应该这样写:
WHERE
`b`.`is_deleted` =0
AND (
`a`.`subcategory_id` = '11'
OR `a`.`subcategory_id` = '1'
OR `a`.`subcategory_id` = '8'
OR `a`.`subcategory_id` = '5'
OR `a`.`subcategory_id` = '2'
OR `a`.`subcategory_id` = '3'
OR `a`.`subcategory_id` = '9'
OR `a`.`subcategory_id` = '4'
OR `a`.`subcategory_id` = '10'
OR `a`.`subcategory_id` = '6'
OR `a`.`subcategory_id` = '7'
)
AND `b`.`ps_keyword` LIKE '%xxxxxxxxxxxxxxxxxxxxxxxxxxxx%' ESCAPE '!'
我建议用中的替换同一列上的这些多个
或
条件:
WHERE
`b`.`is_deleted` = 0
AND `a`.`subcategory_id` IN (11, 1, 8, 5, ..., 7)
AND `b`.`ps_keyword` LIKE '%xxxxxxxxxxxxxxxxxxxxxxxxxxxx%' ESCAPE '!'
注意,我将值列表更改为数字,而不是字符串--这些值看起来像数字,因此应该如此存储和对待它们。