我有:
class Game
{
};
class Zombie :public Game
{
public:
virtual int getHP() const=0;
};
class Zombiesmall : public Zombie
{
int HPy=30;
public:
int getHP() const;
};
class Zombiebig : public Zombie
{
int HPz=20;
public:
int getHP() const;
};
class Player : public Game
{
int hpk=100;
public:
int getHPK() const;
};
class Barrel: public Game
{
};
我的讲师说，gethp和gethpk函数同时存在是没有意义的，所以他让我改变它，他建议在game类中做一个函数，所以我推测他想让我在game类中做virtual函数。 我这样做了，但我的问题是，如果我在类Barrel中根本不需要这个函数，那么这样做是否有意义，但是通过创建虚函数，我无论如何都要在Barrel中编写a定义，而我永远不会使用它。
下面是一个继承树，应该会有所帮助:
Entity (renamed your Game)
<- Creature (with getHP())
<- Player (one of the implementations)
<- Zombie
<- SmallZombie
<- BigZombie
<- Barrel (without getHP())
在C++中:
class Entity { // base for other classes
public:
virtual ~Entity() = default;
};
class Creature : public Entity { // has getHP()
public:
virtual int getHP() const = 0;
};
class Player : public Creature { // is-a Creature => must implement getHP()
private:
int hp = 100;
public:
int getHP() const override {
return hp;
}
};
// similar for zombies
class Barrel : public Entity { // not a Creature => doesn't have getHP()
};
