我正在尝试一个mysql查询来根据距离排序帖子,比如说在半径250英里内,所有的工作都很好,除了我需要以一种方式排序帖子,特色帖子总是在顶部。这是我的mysql查询(我正在wordpress上做)。
SELECT SQL_CALC_FOUND_ROWS wp_posts.*, ( 3959 * acos( cos( radians(40.140711) ) * cos( radians( latitude.meta_value ) ) * cos( radians( longitude.meta_value ) - radians(-74.20619299999998) ) + sin( radians(40.140711) ) * sin( radians( latitude.meta_value ) ) ) ) AS distance ,
latitude.meta_value AS latitude ,
longitude.meta_value AS longitude
FROM wp_posts
INNER JOIN wp_postmeta ON (wp_posts.ID = wp_postmeta.post_id)
INNER JOIN wp_postmeta AS latitude ON wp_posts.ID = latitude.post_id
INNER JOIN wp_postmeta AS longitude ON wp_posts.ID = longitude.post_id
WHERE 1=1
AND wp_posts.post_type = 'event'
AND (wp_posts.post_status = 'publish' OR wp_posts.post_status = 'recurring')
AND (wp_postmeta.meta_key = 'st_date' )
AND latitude.meta_key="geo_latitude"
AND longitude.meta_key="geo_longitude"
AND wp_posts.ID in (SELECT tr.object_id FROM wp_term_relationships tr JOIN wp_term_taxonomy t on t.term_taxonomy_id=tr.term_taxonomy_id WHERE t.term_id IN ('3','4','5','6','7','8','9','10'))
AND (wp_posts.ID IN (SELECT wp_postmeta.post_id FROM wp_postmeta WHERE wp_postmeta.meta_key='st_date'
AND date_format(wp_postmeta.meta_value,'%Y-%m-%d') >'2013-09-23 14:35:58'))
GROUP BY wp_posts.ID HAVING distance <= 250
ORDER BY (SELECT wp_postmeta.meta_value FROM wp_postmeta, wp_posts AS p where wp_postmeta.post_id=p.ID AND wp_postmeta.meta_key = 'featured_h') ASC, distance ASC LIMIT 0, 10
问题是ORDER BY,它给我的错误是“Subquery returns多于1行”
如果删除ORDER BY(从wp_postmeta中选择wp_postmeta.meta_value,wp_posts为p,其中wp_postmeta.post_id=p.id,wp_postmeta.meta_key='featured_h'
它的工作很好,但它没有显示出顶部的fetaured柱子,任何方法来修复它。
在resultset中放置一列,显示featureed
状态。我相信,您必须再次加入wp_postmeta才能实现这一点。
然后使用
ORDER BY status, distance
或者也许
ORDER BY STATUS='featured', distance
这将把你的特色帖子首先按距离排序,然后是其余的。
(将子查询放在order by
子句中是很奇怪的。)