我试图通过从另一个数组列表中筛选数组来重构它。
包含筛选器的数组:
const filteringTags: [
'Kitchen',
'Accessories',
...
]
我要操作的数组:
[
{
category: 'free',
date: '2020-04-04',
title: 'Some Title',
tags: [
'Kitchen',
'Accessories'
]
},
{
category: 'premium',
date: '2020-04-05',
title: 'Another Title',
tags: [
'Kitchen'
]
},
...
]
预期结果:
[
'Kitchen': [
{
category: 'free',
date: '2020-04-04',
title: 'Some Title',
tags: [
'Kitchen',
'Accessories'
]
},
{
category: 'premium',
date: '2020-04-05',
title: 'Another Title',
tags: [
'Kitchen'
]
}
],
'Accessories': [
{
category: 'free',
date: '2020-04-04',
title: 'Some Title',
tags: [
'Kitchen',
'Accessories'
]
}
]
]
我试过的:不幸的是，这里没有什么有用的东西可以张贴。
我尽量避免使用库，所以如果您对使用ES6有任何建议，我将非常感谢。
将所需输出视为对象数组，
null
const data = [
{
category: 'free',
date: '2020-04-04',
title: 'Some Title',
tags: ['Kitchen', 'Accessories'],
},
{
category: 'premium',
date: '2020-04-05',
title: 'Another Title',
tags: ['Kitchen'],
},
];
const filteringTags = ['Kitchen', 'Accessories'];
const getGroupedData = (data, filters) => {
const result = {};
filters.forEach(filter => {
result[filter] = [
...(result[filter] || ''),
...data.filter(d => d.tags.includes(filter)),
];
});
return result;
};
let finalResult = getGroupedData(data, filteringTags);
finalResult = Object.keys(finalResult).map(key => ({
[key]: finalResult[key],
}));
console.log(finalResult);
下面是一个完整的工作示例，它产生了所需的结果:
null
const filteringTags = [
'Kitchen',
'Accessories',
];
const data = [
{
category: 'free',
date: '2020-04-04',
title: 'Some Title',
tags: [
'Kitchen',
'Accessories'
]
},
{
category: 'premium',
date: '2020-04-05',
title: 'Another Title',
tags: [
'Kitchen'
]
},
];
function byTag(tags, data) {
let tagMap = {};
for (let tag of tags) {
tagMap[tag] = [];
for (let datum of data) {
if (datum.tags.includes(tag)) {
tagMap[tag].push(datum);
}
}
}
return tagMap;
}
let result = byTag(filteringTags, data);
console.log(JSON.stringify(result, null, 2));
简短而漂亮的解决你的任务
const filteringTags = [
'Kitchen',
'Accessories',
]
const arr = [
{
category: 'free',
date: '2020-04-04',
title: 'Some Title',
tags: [
'Kitchen',
'Accessories'
]
},
{
category: 'premium',
date: '2020-04-05',
title: 'Another Title',
tags: [
'Kitchen'
]
}
]
const resultArr = filteringTags.map((it, index) => {
return { [it]: arr }
})
如果需要对象，请使用此函数
const resultObj = filteringTags.reduce((acc, it) => {
return { ...acc, [it]: arr }
}, {})
