提问者:小点点

如何在我的不和谐音乐机器人中实现队列系统?


@client.command()
async def play(ctx, *, url = None):
  if ctx.author.voice is None:
      msg = await ctx.send("You are not in a voice channel.")
      await msg.delete(delay = 3)
  voice_channel = ctx.author.voice.channel
  if ctx.voice_client is None:
      await voice_channel.connect()
  else:
      await ctx.voice_client.move_to(voice_channel)

  search_keyword = url
  if not ("youtube.com/watch?" in search_keyword):
    search_keyword = search_keyword.replace(" ", "+")
    html = urllib.request.urlopen(f"https://www.youtube.com/results?search_query={search_keyword}")
    video_ids = re.findall(r"watch\?v=(\S{11})", html.read().decode())
    url = str(f"https://www.youtube.com/watch?v={video_ids[0]}")
  
  ctx.voice_client.stop()
  FFMPEG_OPTIONS = {'before_options': '-reconnect 1 -reconnect_streamed 1 -reconnect_delay_max 5', 'options': '-vn'}
  YDL_OPTIONS = {'format': 'bestaudio', 'noplaylist':'True'}
  vc = ctx.voice_client

  with youtube_dl.YoutubeDL(YDL_OPTIONS) as ydl:
    info = ydl.extract_info(url, download=False)
    title = info.get('title', None)
    length = info['duration']
    url2 = info["formats"][0]["url"]
    source = await discord. FFmpegOpusAudio.from_probe(url2, **FFMPEG_OPTIONS)
    vc.play(source)
  
  embed = discord.Embed(title = "Currently Playing", colour = discord.Colour.blue())
  embed.add_field(name = "Song", value = title, inline = False)
  embed.add_field(name = "Length", value = str(datetime.timedelta(seconds = length)), inline = False)
  embed.add_field(name = "Link", value = url, inline = False)
  msg = await ctx.send(embed=embed)
  await msg.add_reaction("\u23F8")
  await msg.add_reaction("\u25B6")
  await msg.add_reaction("\u23F9")
  while True:
    try:
      reaction, user = await client.wait_for("reaction_add", check=lambda reaction, user: user.id == ctx.author.id and reaction.message.id == msg.id and reaction.emoji in ["\u23F8", "\u25B6", "\u23F9"], timeout = length)
    
    except asyncio.TimeoutError:
      return await msg.clear_reactions()
        
    async def process():
      if reaction.emoji == "\u23F8":
        await msg.remove_reaction(reaction.emoji, ctx.author)
        ctx.voice_client.pause()
      elif reaction.emoji == "\u25B6":
        await msg.remove_reaction(reaction.emoji, ctx.author)
        ctx.voice_client.resume()
      elif reaction.emoji == "\u23F9":
        await msg.remove_reaction(reaction.emoji, ctx.author)
        ctx.voice_client.stop()

    asyncio.create_task(process())

共1个答案

匿名用户

首先,您需要在命令之外创建一个空队列

队列 = {}

还有一个功能来检查队列中是否有一首歌,它会播放这首歌

#check queue
queues = {}
def check_queue(ctx, id):
  if queues[id] !={}:
    voice = ctx.guild.voice_client
    source = queues[id].pop(0)
    voice.play(source, after=lambda x=0: check_queue(ctx, ctx.message.guild.id))

并在play命令中创建一个功能,如果一首歌已经在播放,则将下一首歌添加到队列中,并添加检查队列功能

  if voice.is_playing():
    guild_id = ctx.message.guild.id
    if guild_id in queues:
      queues[guild_id].append(source)
    else:
      queues[guild_id] = [source]
  else:
    vc.play(source, after=lambda x=0: check_queue(ctx, ctx.message.guild.id))

如果你需要更多帮助,你可以在这里查看我的代码需要帮助不和谐机器人队列