我对Java相当陌生，我想生成一个长度为“数字”的随机（x，y）坐标数组，其中不包含重复。x或y值可以重复，但不能有重复的（x，y）坐标。输出不一定是点，只是某种方式来保存坐标的x，y值。
我可以生成一个随机点数组，并尝试使用Set来确保没有重复的值，但遇到了问题。我尝试使用条件“while（set. size）”和应该禁止重复的“add”方法来创建包含唯一点的正确大小的输出。
这是代码：
Set<Point> set = new HashSet<Point>();
Random position = new Random();
Point test=new Point();
do{
test.x=position.nextInt(xx);
test.y=position.nextInt(yy);
//xx and yy are the random number limits called from another part of the code
set.add(test);
}
while (set.size()<number);
List<Object> list = new ArrayList<Object>(set);
Object[] coord = list.toArray();
这将输出一个长度正确的数组，但每个元素都是相同的。有人能提供任何帮助吗？
谢啦
test每次循环时都指向空间中的同一个变量，以修复在循环中创建一个新实例的问题——而不仅仅是在它之前一次：
Set<Point> set = new HashSet<Point>();
Random position = new Random();
Point test;
do{
test = new Point();
test.x=position.nextInt(xx);
test.y=position.nextInt(yy);
//xx and yy are the random number limits called from another part of the code
set.add(test);
}
while (set.size()<number);
List<Object> list = new ArrayList<Object>(set);
Object[] coord = list.toArray();
您正在修改同一个点对象。然而，由于您每次都更改X和Y，因此您也更改了点的哈希码和相等性，因此您最终会在集合中多次放置相同的对象。有趣的案例。
尝试
do{
test = new Point();
test.x=position.nextInt(xx);
test.y=position.nextInt(yy);
//xx and yy are the random number limits called from another part of the code
set.add(test);
}
while (set.size()<number);
取值随机但不重复
Random rndm = new Random();
String[] selectedNumber = new String[15];
String[] sequanceNumber = {"1","2","3","4","5","6","7","8","9","10","11","12","13","14","15"};
//*****FIRST LOOP START*****//
for(byte a = 0; a < 15;){
int temp = rndm.nextInt(15)+1;
//*****SECOND LOOP START*****//
for(byte b = 0; b < 15; b++){
String s4 = temp+"";
//*****CHECKING CONDITION START*****//
if(s4.equals(sequanceNumber[b]) ){
selectedNumber[a] = s4;
String s1 = sequanceNumber[b];
s1 = s1.replace(s1, " ");
sequanceNumber[b] = s1;
a++;
}
//*****CHECKING CONDITION END*****//
}
//*****SECOND LOOP END*****//
}
//*****FIRST LOOP END*****//
//*****PRINT ALL RANDOM VALUES BUT NOT REPEATED VALUES*****//
System.out.println(Arrays.toString(selectedNumber));
