也许你能帮我。我不知道如何对按“标题”分组的一些表格的单元格“年份”进行求和。我需要那个求和单元格也将合并为第一个单元格“标题”。
我使用sum（），但它返回0。
XML代码：
<?xml version="1.0" encoding="UTF-8"?>
<LIST>
<Row>
<TITLE>Empire Burlesque</TITLE>
<YEAR>2001</YEAR>
<artist>Bob Dylan</artist>
<artist1>Bob Dylan1</artist1>
</Row>
<Row>
<TITLE>Empire Burlesque</TITLE>
<YEAR>2002</YEAR>
<artist>Bob Dylan</artist>
<artist1>Bob Dylanas</artist1>
</Row>
<Row>
<TITLE>Empire Burlesque</TITLE>
<YEAR>2003</YEAR>
<artist>Bonnie Tyler</artist>
<artist1>Bob Dylan</artist1>
</Row>
<Row>
<TITLE>Empire Burlesque</TITLE>
<YEAR>2004</YEAR>
<artist>Bonnie Tyler</artist>
<artist1>Bob Dylanas</artist1>
</Row>
<Row>
<TITLE>Empire Burlesque1</TITLE>
<YEAR>2005</YEAR>
<artist>Bonnie Tyler</artist>
<artist1>Bob Dylan</artist1>
</Row>
<Row>
<TITLE>Empire Burlesque1</TITLE>
<YEAR>2006</YEAR>
<artist>Bonnie Tyler</artist>
<artist1>Bob Dylanas</artist1>
</Row>
</LIST>
XSLT代码：
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" doctype-public="XSLT-compat" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:key name="cds" match="Row" use="TITLE" />
<xsl:template match="/">
<html>
<body>
<h2>My CD Collection</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Title</th>
<th>Year</th>
<th>Artist</th>
<th>Artist1</th>
</tr>
<xsl:for-each select="LIST/Row[generate-id() = generate-id(key('cds', TITLE)[1])]" >
<tr>
<td>
<xsl:if test="key('cds', TITLE)[1]">
<xsl:attribute name="rowspan">
<xsl:value-of select="count(key('cds', TITLE))" />
</xsl:attribute>
</xsl:if>
<xsl:value-of select="TITLE"/>
</td>
<td>
<xsl:value-of select="YEAR"/>
</td>
<td>
<xsl:value-of select="artist"/>
</td>
<td>
<xsl:value-of select="artist1"/>
</td>
</tr>
<xsl:for-each select="key('cds', TITLE)[position() > 1]">
<tr>
<td>
<xsl:value-of select="YEAR"/>
</td>
<td>
<xsl:value-of select="artist"/>
</td>
<td>
<xsl:value-of select="artist1"/>
</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
现在的结果是：
尝试sum（key（'cds'， TITLE）/YEAR）在for-each中。
