我正在寻找一种使用jstl填充下拉列表的方法。我需要在页面加载时执行此操作。我尝试了一些代码。但它不起作用。

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>  
 <select>
         <c:forEach items="${requestScope.personList}"  var="person">
         <option value="${person.getId()}">${person.getName()}
         </option>
         </c:forEach>
 </select>

这是我的控制器servlet代码。

    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    response.setContentType("text/html;charset=UTF-8");
    try {
        CasualLeaveService service1 = new CasualLeaveServiceImpl();
        List<Person> personList = service1.searchName();
        request.setAttribute("personList", personList);
        RequestDispatcher rd = getServletContext().getRequestDispatcher("/casual");
        rd.forward(request, response);
    } catch (Exception e) {
        e.printStackTrace();
    }
}

这是我的服务器类代码。

public List<Person> searchName() {
    List<Person> list = null;
    try (DaoSession session = DaoSessionFactory.createSession()) {
        EmployeeDao emp = session.getEmployeeDao();
        list = emp.findAllPersons();
        if (!list.isEmpty()) {
            System.out.println("My list is :"+list);
        } else {
            System.out.println("Error in list");
        }
    }
    return list;
}

我的人类

    public class Person {

private int id;
private String employeeNo;
private String name;

@ValidNo(message = "Must be a number between 1 to 999")
private Integer epfNo;

public Person() {
}

/**
 *
 * @param id
 * @param employeeNo
 * @param name initials + surname
 * @param epfNo
 */
public Person(int id, String employeeNo, String name, Integer epfNo) {
    this.id = id;
    this.employeeNo = employeeNo;
    this.name = name;
    this.epfNo = epfNo;
}

public int getId() {
    return id;
}

public void setId(int id) {
    this.id = id;
}

public String getEmployeeNo() {
    return employeeNo;
}

public void setEmployeeNo(String employeeNo) {
    this.employeeNo = employeeNo;
}

/**
 *
 * @return initials + surname
 */
public String getName() {
    return name;
}

/**
 *
 * @param name initials + surname
 */
public void setName(String name) {
    this.name = name;
}

public Integer getEpfNo() {
    return epfNo;
}

public void setEpfNo(Integer epfNo) {
    this.epfNo = epfNo;
}

@Override
public int hashCode() {
    int hash = 7;
    hash = 67 * hash + this.id;
    return hash;
}

@Override
public boolean equals(Object obj) {
    if (obj == null) {
        return false;
    }
    if (getClass() != obj.getClass()) {
        return false;
    }
    final Person other = (Person) obj;
    return this.id == other.id;
}

}

我的Web. xml是这样映射的。

<servlet>
    <jsp-file>/WEB-INF/views/leave/CasualLeave.jsp</jsp-file>
    <servlet-name>casualLeave</servlet-name>
</servlet>

<servlet-mapping>
    <servlet-name>casualLeave</servlet-name>
    <url-pattern>/casual</url-pattern>
</servlet-mapping>

我可以保证服务类工作得很好。因为我刚刚将这个服务类方法直接调用到jsp并且输出是完美的。问题是使用jstl这个方法不起作用。
你能告诉我错误是什么吗。因为我不喜欢在jsp html代码中使用scriptlet标签。我听说这是不好的做法。
谢谢你。