我正在尝试发送以下内容,但收到以下错误。TableUser实现了可序列化,但问题似乎是FXCollections,但我不知道如何序列化。
这是Tableuser类。
package application;
import java.io.Serializable;
public class TableUser implements Serializable{
private static final long serialVersionUID = 1L;
private String username = "";
public TableUser(String name) {
this.username = name;
}
public String getUsername(){
return username;
}
public void setUsername(String user){
username = user;
}
}
//NOT apart of TableUser - This is the code that isn't working
private static ObservableList<TableUser> clientList = FXCollections.observableArrayList();
Object[] data = new Object[2];
data[0] = "CLIENTS";
data[1] = clientList;
for(int i = 0; i < clients.size(); i++){
clients.get(i).sendData(data);
}
//I don't know if this helps but here is the sendData method
protected void sendData(Object[] data){
try {
oos.writeObject(data); //ServerMultiClient.java:286
oos.reset();
} catch (IOException e) {
e.printStackTrace();
}
}
//This is from the Client application that is also part of the issue
if((fromServer = (Object[]) ois.readObject()) != null){ //Controller.java:109
java.io.WriteAbortedException: writing aborted; java.io.NotSerializableException: com.sun.javafx.collections.ObservableListWrapper
at java.io.ObjectInputStream.readObject0(Unknown Source)
at java.io.ObjectInputStream.readArray(Unknown Source)
at java.io.ObjectInputStream.readObject0(Unknown Source)
at java.io.ObjectInputStream.readObject(Unknown Source)
at application.ChatRoomController$2.run(Controller.java:109)
at java.lang.Thread.run(Unknown Source)
Caused by: java.io.NotSerializableException: com.sun.javafx.collections.ObservableListWrapper
at java.io.ObjectOutputStream.writeObject0(Unknown Source)
at java.io.ObjectOutputStream.writeArray(Unknown Source)
at java.io.ObjectOutputStream.writeObject0(Unknown Source)
at java.io.ObjectOutputStream.writeObject(Unknown Source)
at application.ServerMultiClient.sendData(ServerMultiClient.java:286)
at application.ServerMultiClient.run(ServerMultiClient.java:236)
鉴于< code > observablelist wrapper 是不可序列化的,您可以尝试循环访问< code>TableUser对象,并将它们逐个添加到< code>data中
大概是这样的:
Object[] data = new Object[clientList.size()+1];
data[0] = "CLIENTS";
int counter = 1;
for(TableUser tu: clientList) {
data[counter] = tu;
counter++;
}
当试图序列化的对象没有实现Seriezable
类时,会抛出一个NotSeri的可序列化异常
。在您的例子中,因为它告诉您的可序列化列表
是不可序列化的,所以我推断clientList
是不可序列化的。
您可以不使用Java FX < code > observable list ,而是使用一个列表,例如< code>java.util.ArrayList,它恰好实现了< code>Serializable。