我是新的编程和尝试一个程序，你需要猜测一个视频游戏角色的名字，只有3个猜测，如果你用完猜测你将失去。我在这里用了一个do-while循环，这样我就可以一遍又一遍地做。。。这里的问题是，每次循环再次启动时，它会显示2次提示，即使它应该是1次提示，但它显示了2次提示。你能帮帮我吗？也许我的算法做错了，谢谢！
#include <iostream>
using namespace std;
int main()
{
char rerun_option;
do {
string secretWord = "Arthur Morgan";
string guess;
int guessCount = 0;
int guessLimit = 3;
bool outofGuesses = false;
while (secretWord != guess && !outofGuesses) {
if (guessCount < guessLimit) {
cout << "Enter video game character name guess: ";
getline(cin, guess);
guessCount++;
}
else {
outofGuesses = true;
}
}
if (outofGuesses) {
cout << "You Lose!" << endl;
outofGuesses = false;
}
else {
cout << "You Win!" << endl;
}
cout << "Try Again?(Y/N) ";
cin >> rerun_option;
} while (rerun_option == 'Y' || rerun_option == 'y');
return 0;
}
编辑:stackoverflow.com/a/21567292/4645334是您的问题的一个很好的例子，解释了您为什么会遇到它，并解释了您如何解决它。我在下面提供了您的代码的工作示例，以及指向有关cin.ignore（）的使用和描述的更多信息的链接。
#include <iostream>
using namespace std;
int main()
{
char rerun_option;
do {
string secretWord = "Arthur Morgan";
string guess;
int guessCount = 0;
int guessLimit = 3;
bool outofGuesses = false;
while (secretWord != guess && !outofGuesses) {
if (guessCount < guessLimit) {
cout << "Enter video game character name guess: ";
cin.ignore(); // <-- ADD THIS LINE RIGHT HERE
getline(cin, guess);
guessCount++;
}
else {
outofGuesses = true;
}
}
if (outofGuesses) {
cout << "You Lose!" << endl;
outofGuesses = false;
}
else {
cout << "You Win!" << endl;
}
cout << "Try Again?(Y/N) ";
cin >> rerun_option;
} while (rerun_option == 'Y' || rerun_option == 'y');
return 0;
}
https://www.tutorialspoint.com/what-is-the-use-of-cin-ignore-in-cplusplus
