我一直在阅读和研究，但我很难弄清楚如何为主干/木偶项目组织嵌套的复杂视图。在一个复合视图中的两个集合中的答案与我认为需要的非常接近，但在处理其中一个集合项中的多个视图时，它似乎有不足之处。

我将通过扩展这个问题的答案来解释。

假设我们有一套公寓，一套他们的房间，列出了他们的椅子。此外，让我们添加公寓租户。作为租户视图的想法可以有自己的视图管理、事件，并且可以在站点的其他地方重用。

根据我的理解，它可能看起来像：

• ApartmentCollectionView（CollectionView）

我的问题是ApartmentView不允许多个子视图。

@scott-puleo提供的答案副本，并添加了租户。

var apartments = [
    {apartment: '1a',
        rooms: [
            {name: 'master bed', chairs: []},
            {name: 'kitchen', chairs: [
                {chairType: 'stool'}, {chairType: 'stool'}]},
            {name: 'living room', chairs: [
                {chairType: 'sofa'}, {chairType: 'love seat'}]}],
        tenant:{name:Bob Jones,phone:6165551234}
    },
    {apartment: '2a', 
        rooms: [
            {name: 'master bed', chairs: []},
            {name: 'kitchen', chairs: [
                {chairType: 'shaker'}, {chairType: 'shaker'}]},
            {name: 'living room', chairs: [
                {chairType: 'sectional'}]}]
        tenant:{name:Hope Smith,phone:6365551234}
    }];

var chairModel = Backbone.Model.extend({});

var roomModel = Backbone.Model.extend({
    initialize: function(attributes, options) {
        this.chairs = new Array();
        _.each(attributes.chairs, function(chair){
          this.chairs.push(new chairModel(chair));    
        }, this);
    }          
});

var ApartmentModel = Backbone.Model.extend({
    initialize: function(attributes, options) {
        this.rooms = new Array();
        _.each(attributes.rooms, function(room){
          this.rooms.push(new roomModel(room));    
        }, this);
    }  
}); 

var ApartmentCollection = Backbone.Collection.extend({
    model: ApartmentModel
});

var ChairView = Backbone.Marionette.ItemView.extend({
    template:'#chair'
});

var TenantView = Backbone.Marionette.ItemView.extend({
    template:'#tenant'
});

var RoomView = Backbone.Marionette.CompositeView.extend({
    template: '#room',
    itemViewContainer: 'ul',
    itemView: ChairView,
    initialize: function(){
        var chairs = this.model.get('chairs');
        this.collection = new Backbone.Collection(chairs);
    }
});   

var ApartmentView = Backbone.Marionette.CompositeView.extend({
    template: '#appartment',
    itemViewContainer: 'ul',
    itemView: RoomView,      // Composite View
    initialize: function(){
        var rooms = this.model.get('rooms');
        this.collection = new Backbone.Collection(rooms);
    }
});   

var ApartmentCollectionView = Backbone.Marionette.CollectionView.extend({
    itemView: ApartmentView  // Composite View
});

apartmentCollection = new ApartmentCollection(apartments);

apartmentCollectionView = new ApartmentCollectionView({
    collection: apartmentCollection
});    

App.apartments.show(apartmentCollectionView);

我觉得我应该考虑为每个公寓启动单独的布局或控制器，但这不是有效的，我也不认为这是他们的目的。这些也可能使在区域中管理ID变得棘手。

谢谢你的指导，我会更新我可能发现的任何答案。