我正在输出MySQL查询的结果，该查询包含有关用户和所选主题的信息。 其中一行包含电子邮件地址。 我希望php只将此行作为超链接输出，而将其余部分作为文本保留。 我该怎么做？
$resultSet = $db->query ("...my query");
echo $resultSet -> num_rows;
While($rows = $resultSet ->fetch_assoc())
{
$subject [1] = $rows['First_Name'];
$subject [2] = $rows['Surname'];
$subject [3] = $rows['Email_Address'];
$subject [4] = $rows['Subject1'];
$subject [5] = $rows['Subject2'];
$subject [6] = $rows['Subject2'];
$subjectOutput = array_filter($subject, 'strlen');
$subjectString = implode($subjectOutput, '<br/>');
$output .= "<p> ". $subjectString." </p>";
}
试试这个
$resultSet = $db->query ("...my query");
echo $resultSet -> num_rows;
While($rows = $resultSet ->fetch_assoc())
{
$subject [1] = $rows['First_Name'];
$subject [2] = $rows['Surname'];
$subject [3] = "<a href='mailto:" . $rows['Email_Address'] . ">" . $rows['Email_Address'] . "</a>";
$subject [4] = $rows['Subject1'];
$subject [5] = $rows['Subject2'];
$subject [6] = $rows['Subject2'];
$subjectOutput = array_filter($subject, 'strlen');
$subjectString = implode($subjectOutput, '<br/>');
$output .= "<p> ". $subjectString." </p>";
}
