Java Integer lowestOneBit()方法

java.lang.Integer.lowestOneBit() 方法在指定的int值返回一个int值最多单个1位，在最低阶(“最右”)1位的位置。它返回零，如果指定的值没有一个位在其二进制补码表示法，即，如果它等于零。

1 语法

public static int lowestOneBit(int i)

2 参数

i ： 这是int值。

3 返回值

此方法返回一个int值和单个1位，在指定的值最低阶1位的位置，或者零，如果指定值本身等于零。

4 示例 

package com.yiidian;

/**
 * 一点教程网： http://www.yiidian.com
 */
/**
 * Java Integer lowestOneBit()方法
 */
import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

     int i = 170;
     System.out.println("Number = " + i);
    
     /* returns the string representation of the unsigned integer value 
     represented by the argument in binary (base 2) */
     System.out.println("Binary = " + Integer.toBinaryString(i));

     // returns the number of one-bits 
     System.out.println("Number of one bits = " + Integer.bitCount(i));

     /* returns an int value with at most a single one-bit, in the position 
     of the highest-order ("leftmost") one-bit in the specified int value */
     System.out.println("Highest one bit = " + Integer.highestOneBit(i));

     /* returns an int value with at most a single one-bit, in the position
     of the lowest-order ("rightmost") one-bit in the specified int value.*/
     System.out.println("Lowest one bit = " + Integer.lowestOneBit(i));
   }
}

输出结果为：

Number = 170
Binary = 10101010
Number of one bits = 4
Highest one bit = 128
Lowest one bit = 2