Spring Async DeferredResult在Tomcat 8中不起作用
问题内容:
我使用Spring 4.0.5和Servlet API 3.1.0创建了一个异步MVC应用程序。异步行为在使用Firefox 24的Jetty
8.0中运行良好,但是我无法使其在Tomcat 8.0和Firefox
24中正常工作。我正在使用DeferredResult管理异步请求。知道我缺少什么吗?这可能是某些Tomcat设置或web.xml中的某些内容,因为完全相同的Java代码在Jetty中可以很好地工作。
当异步请求最终产生结果并且应该写入响应时,我看到记录了以下消息:
WebAsyncManager - Dispatching request to resume processing
RequestResponseBodyMethodProcessor - Written [true] as "application/json" using MappingJacksonHttpMessageConvertor
DispatcherServlet - Null ModelAndView returned to DispatcherServlet with name 'app': assuming HandlerAdapter completed request handling
DispatcherServlet - Successfully completed request
长时间运行的请求永远不会回到我的浏览器,最终我在Tomcat日志中看到此超时错误:
CoyoteAdapter.asyncDispatch Exception while processing an asynchronous
request
java.lang.IllegalStateException: Calling [asyncTimeout()] is not valid
for a request with Async state [Dispatching]
--server.xml–
<Connector port="8080" protocol="org.apache.coyote.http11.Http11NioProtocol"
maxConnections="100"
maxThreads="100"
connectionTimeout="150000"
asyncTimeout="150000" />
--Tomcat web.xml–
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<servlet>
<servlet-name>default</servlet-name>
<servlet-class>org.apache.catalina.servlets.DefaultServlet</servlet-class>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<init-param>
<param-name>listings</param-name>
<param-value>false</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
<async-supported>true</async-supported>
</servlet>
<servlet>
<servlet-name>jsp</servlet-name>
<servlet-class>org.apache.jasper.servlet.JspServlet</servlet-class>
<init-param>
<param-name>fork</param-name>
<param-value>false</param-value>
</init-param>
<init-param>
<param-name>xpoweredBy</param-name>
<param-value>false</param-value>
</init-param>
<load-on-startup>3</load-on-startup>
<async-supported>true</async-supported>
</servlet>
<!-- The mapping for the default servlet -->
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- The mappings for the JSP servlet -->
<servlet-mapping>
<servlet-name>jsp</servlet-name>
<url-pattern>*.jsp</url-pattern>
<url-pattern>*.jspx</url-pattern>
</servlet-mapping>
</web-app>
-Spring web-app web.xml–
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>my-async-app</param-value>
</context-param>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/app-config.xml</param-value>
</context-param>
<!-- Handles all requests into the application -->
<servlet>
<servlet-name>app</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/controllers-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
<async-supported>true</async-supported>
</servlet>
<!-- Maps all /app requests to the DispatcherServlet for handling -->
<servlet-mapping>
<servlet-name>app</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
</web-app>
问题答案:
描述的是关系到Tomcat的一个bug这个问题在这里,这里和这里。
可能的解决方案:
- 使用更稳定的Tomcat版本,例如Tomcat 7.0.47,该错误已得到修复。
- 使用更高级的调度程序,例如org.springframework.web.servlet.DispatcherServlet
- 按照此处的建议覆盖HttpServlet :
public class AsyncServlet extends HttpServlet { protected void doGet(final HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (request.isAsyncStarted()) { response.getWriter().write("asyncResult=" + request.getAttribute("asyncResult")); } else { final AsyncContext asyncContext = request.startAsync(request, response); asyncContext.addListener(new AsyncListener() { public void onTimeout(AsyncEvent event) throws IOException { request.setAttribute("asyncResult", "timeout\n"); asyncContext.dispatch(); } public void onStartAsync(AsyncEvent event) throws IOException { } public void onError(AsyncEvent event) throws IOException { } public void onComplete(AsyncEvent event) throws IOException { } }); asyncContext.setTimeout(5000L); } }
}